Optimal. Leaf size=164 \[ \frac{(d e-c f) \tan ^{-1}\left (\frac{\sqrt{f} x}{\sqrt{e}}\right ) (b e (5 d e-c f)-a f (c f+3 d e))}{2 e^{3/2} f^{7/2}}+\frac{d x \left (c+d x^2\right ) (5 b e-3 a f)}{6 e f^2}-\frac{d x (b e (15 d e-13 c f)-3 a f (3 d e-c f))}{6 e f^3}-\frac{x \left (c+d x^2\right )^2 (b e-a f)}{2 e f \left (e+f x^2\right )} \]
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Rubi [A] time = 0.232371, antiderivative size = 164, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.154, Rules used = {526, 528, 388, 205} \[ \frac{(d e-c f) \tan ^{-1}\left (\frac{\sqrt{f} x}{\sqrt{e}}\right ) (b e (5 d e-c f)-a f (c f+3 d e))}{2 e^{3/2} f^{7/2}}+\frac{d x \left (c+d x^2\right ) (5 b e-3 a f)}{6 e f^2}-\frac{d x (b e (15 d e-13 c f)-3 a f (3 d e-c f))}{6 e f^3}-\frac{x \left (c+d x^2\right )^2 (b e-a f)}{2 e f \left (e+f x^2\right )} \]
Antiderivative was successfully verified.
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Rule 526
Rule 528
Rule 388
Rule 205
Rubi steps
\begin{align*} \int \frac{\left (a+b x^2\right ) \left (c+d x^2\right )^2}{\left (e+f x^2\right )^2} \, dx &=-\frac{(b e-a f) x \left (c+d x^2\right )^2}{2 e f \left (e+f x^2\right )}-\frac{\int \frac{\left (c+d x^2\right ) \left (-c (b e+a f)-d (5 b e-3 a f) x^2\right )}{e+f x^2} \, dx}{2 e f}\\ &=\frac{d (5 b e-3 a f) x \left (c+d x^2\right )}{6 e f^2}-\frac{(b e-a f) x \left (c+d x^2\right )^2}{2 e f \left (e+f x^2\right )}-\frac{\int \frac{c (b e (5 d e-3 c f)-3 a f (d e+c f))+d (b e (15 d e-13 c f)-3 a f (3 d e-c f)) x^2}{e+f x^2} \, dx}{6 e f^2}\\ &=-\frac{d (b e (15 d e-13 c f)-3 a f (3 d e-c f)) x}{6 e f^3}+\frac{d (5 b e-3 a f) x \left (c+d x^2\right )}{6 e f^2}-\frac{(b e-a f) x \left (c+d x^2\right )^2}{2 e f \left (e+f x^2\right )}+\frac{((d e-c f) (b e (5 d e-c f)-a f (3 d e+c f))) \int \frac{1}{e+f x^2} \, dx}{2 e f^3}\\ &=-\frac{d (b e (15 d e-13 c f)-3 a f (3 d e-c f)) x}{6 e f^3}+\frac{d (5 b e-3 a f) x \left (c+d x^2\right )}{6 e f^2}-\frac{(b e-a f) x \left (c+d x^2\right )^2}{2 e f \left (e+f x^2\right )}+\frac{(d e-c f) (b e (5 d e-c f)-a f (3 d e+c f)) \tan ^{-1}\left (\frac{\sqrt{f} x}{\sqrt{e}}\right )}{2 e^{3/2} f^{7/2}}\\ \end{align*}
Mathematica [A] time = 0.0925017, size = 134, normalized size = 0.82 \[ \frac{(d e-c f) \tan ^{-1}\left (\frac{\sqrt{f} x}{\sqrt{e}}\right ) (b e (5 d e-c f)-a f (c f+3 d e))}{2 e^{3/2} f^{7/2}}-\frac{x (b e-a f) (d e-c f)^2}{2 e f^3 \left (e+f x^2\right )}+\frac{d x (a d f+2 b c f-2 b d e)}{f^3}+\frac{b d^2 x^3}{3 f^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.009, size = 299, normalized size = 1.8 \begin{align*}{\frac{{d}^{2}{x}^{3}b}{3\,{f}^{2}}}+{\frac{a{d}^{2}x}{{f}^{2}}}+2\,{\frac{bcdx}{{f}^{2}}}-2\,{\frac{b{d}^{2}ex}{{f}^{3}}}+{\frac{ax{c}^{2}}{2\,e \left ( f{x}^{2}+e \right ) }}-{\frac{axcd}{f \left ( f{x}^{2}+e \right ) }}+{\frac{exa{d}^{2}}{2\,{f}^{2} \left ( f{x}^{2}+e \right ) }}-{\frac{bx{c}^{2}}{2\,f \left ( f{x}^{2}+e \right ) }}+{\frac{bxecd}{{f}^{2} \left ( f{x}^{2}+e \right ) }}-{\frac{{e}^{2}xb{d}^{2}}{2\,{f}^{3} \left ( f{x}^{2}+e \right ) }}+{\frac{a{c}^{2}}{2\,e}\arctan \left ({fx{\frac{1}{\sqrt{ef}}}} \right ){\frac{1}{\sqrt{ef}}}}+{\frac{acd}{f}\arctan \left ({fx{\frac{1}{\sqrt{ef}}}} \right ){\frac{1}{\sqrt{ef}}}}-{\frac{3\,a{d}^{2}e}{2\,{f}^{2}}\arctan \left ({fx{\frac{1}{\sqrt{ef}}}} \right ){\frac{1}{\sqrt{ef}}}}+{\frac{b{c}^{2}}{2\,f}\arctan \left ({fx{\frac{1}{\sqrt{ef}}}} \right ){\frac{1}{\sqrt{ef}}}}-3\,{\frac{bcde}{{f}^{2}\sqrt{ef}}\arctan \left ({\frac{fx}{\sqrt{ef}}} \right ) }+{\frac{5\,b{d}^{2}{e}^{2}}{2\,{f}^{3}}\arctan \left ({fx{\frac{1}{\sqrt{ef}}}} \right ){\frac{1}{\sqrt{ef}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.59117, size = 1150, normalized size = 7.01 \begin{align*} \left [\frac{4 \, b d^{2} e^{2} f^{3} x^{5} - 4 \,{\left (5 \, b d^{2} e^{3} f^{2} - 3 \,{\left (2 \, b c d + a d^{2}\right )} e^{2} f^{3}\right )} x^{3} - 3 \,{\left (5 \, b d^{2} e^{4} + a c^{2} e f^{3} - 3 \,{\left (2 \, b c d + a d^{2}\right )} e^{3} f +{\left (b c^{2} + 2 \, a c d\right )} e^{2} f^{2} +{\left (5 \, b d^{2} e^{3} f + a c^{2} f^{4} - 3 \,{\left (2 \, b c d + a d^{2}\right )} e^{2} f^{2} +{\left (b c^{2} + 2 \, a c d\right )} e f^{3}\right )} x^{2}\right )} \sqrt{-e f} \log \left (\frac{f x^{2} - 2 \, \sqrt{-e f} x - e}{f x^{2} + e}\right ) - 6 \,{\left (5 \, b d^{2} e^{4} f - a c^{2} e f^{4} - 3 \,{\left (2 \, b c d + a d^{2}\right )} e^{3} f^{2} +{\left (b c^{2} + 2 \, a c d\right )} e^{2} f^{3}\right )} x}{12 \,{\left (e^{2} f^{5} x^{2} + e^{3} f^{4}\right )}}, \frac{2 \, b d^{2} e^{2} f^{3} x^{5} - 2 \,{\left (5 \, b d^{2} e^{3} f^{2} - 3 \,{\left (2 \, b c d + a d^{2}\right )} e^{2} f^{3}\right )} x^{3} + 3 \,{\left (5 \, b d^{2} e^{4} + a c^{2} e f^{3} - 3 \,{\left (2 \, b c d + a d^{2}\right )} e^{3} f +{\left (b c^{2} + 2 \, a c d\right )} e^{2} f^{2} +{\left (5 \, b d^{2} e^{3} f + a c^{2} f^{4} - 3 \,{\left (2 \, b c d + a d^{2}\right )} e^{2} f^{2} +{\left (b c^{2} + 2 \, a c d\right )} e f^{3}\right )} x^{2}\right )} \sqrt{e f} \arctan \left (\frac{\sqrt{e f} x}{e}\right ) - 3 \,{\left (5 \, b d^{2} e^{4} f - a c^{2} e f^{4} - 3 \,{\left (2 \, b c d + a d^{2}\right )} e^{3} f^{2} +{\left (b c^{2} + 2 \, a c d\right )} e^{2} f^{3}\right )} x}{6 \,{\left (e^{2} f^{5} x^{2} + e^{3} f^{4}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 3.64659, size = 479, normalized size = 2.92 \begin{align*} \frac{b d^{2} x^{3}}{3 f^{2}} + \frac{x \left (a c^{2} f^{3} - 2 a c d e f^{2} + a d^{2} e^{2} f - b c^{2} e f^{2} + 2 b c d e^{2} f - b d^{2} e^{3}\right )}{2 e^{2} f^{3} + 2 e f^{4} x^{2}} - \frac{\sqrt{- \frac{1}{e^{3} f^{7}}} \left (c f - d e\right ) \left (a c f^{2} + 3 a d e f + b c e f - 5 b d e^{2}\right ) \log{\left (- \frac{e^{2} f^{3} \sqrt{- \frac{1}{e^{3} f^{7}}} \left (c f - d e\right ) \left (a c f^{2} + 3 a d e f + b c e f - 5 b d e^{2}\right )}{a c^{2} f^{3} + 2 a c d e f^{2} - 3 a d^{2} e^{2} f + b c^{2} e f^{2} - 6 b c d e^{2} f + 5 b d^{2} e^{3}} + x \right )}}{4} + \frac{\sqrt{- \frac{1}{e^{3} f^{7}}} \left (c f - d e\right ) \left (a c f^{2} + 3 a d e f + b c e f - 5 b d e^{2}\right ) \log{\left (\frac{e^{2} f^{3} \sqrt{- \frac{1}{e^{3} f^{7}}} \left (c f - d e\right ) \left (a c f^{2} + 3 a d e f + b c e f - 5 b d e^{2}\right )}{a c^{2} f^{3} + 2 a c d e f^{2} - 3 a d^{2} e^{2} f + b c^{2} e f^{2} - 6 b c d e^{2} f + 5 b d^{2} e^{3}} + x \right )}}{4} + \frac{x \left (a d^{2} f + 2 b c d f - 2 b d^{2} e\right )}{f^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.16065, size = 263, normalized size = 1.6 \begin{align*} \frac{{\left (a c^{2} f^{3} + b c^{2} f^{2} e + 2 \, a c d f^{2} e - 6 \, b c d f e^{2} - 3 \, a d^{2} f e^{2} + 5 \, b d^{2} e^{3}\right )} \arctan \left (\sqrt{f} x e^{\left (-\frac{1}{2}\right )}\right ) e^{\left (-\frac{3}{2}\right )}}{2 \, f^{\frac{7}{2}}} + \frac{{\left (a c^{2} f^{3} x - b c^{2} f^{2} x e - 2 \, a c d f^{2} x e + 2 \, b c d f x e^{2} + a d^{2} f x e^{2} - b d^{2} x e^{3}\right )} e^{\left (-1\right )}}{2 \,{\left (f x^{2} + e\right )} f^{3}} + \frac{b d^{2} f^{4} x^{3} + 6 \, b c d f^{4} x + 3 \, a d^{2} f^{4} x - 6 \, b d^{2} f^{3} x e}{3 \, f^{6}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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